Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 10 - Review Exercises - Page 816: 6

Answer

$(x+2)^2+(y-4)^2=36$

Work Step by Step

Use standard form of equation of circles; $(x-a)^2+(y-b)^2=r^2$ Here, $r$ defines radius and $(a,b)$ defines center. Thus, $(x-(-2))^2+(y-4)^2=(6)^2$ or, $(x+2)^2+(y-4)^2=36$
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