Answer
If $7^{-2}$ is raised to the third power, the result is a number between 0 and 1.
--> The statement makes sense.
Work Step by Step
$7^{-2}$ is raised to the third power can be written as: $(7^{-2})^{3}$.
Evaluate.
Recall the power rule: $(a^{m})^{n}=a^{mn}$
Thus,
$$(7^{-2})^{3} = 7^{-6}$$
Recall the negative exponent rule: $a^{−n}=\frac{1}{a^{n}}$
Thus,
$$7^{-6} = \frac{1}{7^{6}}$$
$\frac{1}{7^{6}}$ is a number that lies between $0$ and $1$; hence, the statement makes sense.
