## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 66: 22

#### Answer

Angles (in order: 1st, 2nd, 3rd): $58^{\circ},\ 60^{\circ}$, $62^{\circ}.$

#### Work Step by Step

From the text, we build expressions relating the angles: $\left[\begin{array}{llll} \text{ 1st angle, } A & = & A & \text{ ...an even number }\\ \text{ 2nd angle, } B & = & A+2 & \text{ ...next even number }\\ \text{ 3rd angle, } C & = & A+4 & \text{ ...next even number } \end{array}\right.$ $A+(A+2)+(A+4)=180^{\circ}\qquad$... sum of angles is $180^{\circ}$ ... solve for $A$ $3A+6^{\circ}=180^{\circ}$ $3A=174^{\circ}$ $A=58^{\circ}$ the other two angles are: $B=60^{\circ},\ C= 62^{\circ}.$ Angles (in order: 1st, 2nd, 3rd): $58^{\circ},\ 60^{\circ}$, $62^{\circ}.$

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