## Intermediate Algebra for College Students (7th Edition)

Angles (in order: 1st, 2nd, 3rd): $94^{\circ},\ 47^{\circ},\ 39^{\circ}$
From the text, we build expressions relating the angles: $\left[\begin{array}{lll} \text{ 1st angle, } A & = & 2B\\ \text{ 2nd angle, } B & = & B\\ \text{ 3rd angle, } C & = & B-8 \end{array}\right.$ $A+B+C=180\qquad$... sum of angles is $180^{\circ}$ ... replace A and C with corresponding expressions $2B+B+B-8=180\qquad$... solve for B $4B-8=180$ $4B=188$ $B=47^{\circ}$ Back substitute: $A=2B=94^{\circ}$ $C=B-8^{\circ}=39^{\circ}$ Angles (in order: 1st, 2nd, 3rd): $94^{\circ},\ 47^{\circ},\ 39^{\circ}$