Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 53: 101

Answer

$2$

Work Step by Step

Since, we have $\dfrac{7x+4}{b}+13=x$ Multiply the bot sides by $b$ Thus,$7x+4+13b=xb$ or, $7x+4=b(x-13)$ Plug $x=-6$ Therefore, $7(-6)+4=b(-6-13)$ or, $-38=-19b$ Hence, $b=2$
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