Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.4 - Solving Linear Equations - Exercise Set - Page 53: 102



Work Step by Step

Since, we have $\dfrac{-1}{5}-\dfrac{-1}{2}$ or,$=\dfrac{-1}{5}+\dfrac{1}{2}$ Here, LCD=10 $=\dfrac{-2}{10}+\dfrac{5}{10}$ $=\dfrac{-2+5}{10}$ Hence, the result is $\dfrac{3}{10}$
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