Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.1 - Algebraic Expressions, Real Numbers, and Interval Notation - Exercise Set - Page 13: 84



Work Step by Step

$\frac{14}{19}+\frac{5}{19}=\frac{19}{19}=1$, and 1 is an element of the natural numbers, so that means the first statement is true. $12\times(50)^{2}\times(50+10)-12\times(50+10)\times(50)^{2}=0$ $30000\times60-720\times2500=0$ $1800000-1800000=0$ $0=0$, the second statement is also true. Since both of the statements are true, the answer is $true$.
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