Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 98: 27

Answer

$-\dfrac{3}{35}$

Work Step by Step

The product of two numbers with opposite signs is negative. Thus, $\require{cancel} (\frac{2}{7})(-\frac{3}{10}) \\=-\frac{2(3)}{7(10)} \\=-\frac{\cancel{2}(3)}{7\cancel{(10)}5} \\=-\frac{3}{35}$
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