## Intermediate Algebra for College Students (7th Edition)

$-\dfrac{1}{10}$
Make the fractions similar using their LCD of 10 as denominator to obtain: $=-(\frac{3\cdot2}{5\cdot2}) - (-\frac{1\cdot5}{2\cdot5}) \\=-\frac{6}{10} - (-\frac{5}{10})$ RECALL: $a-b = a+(-b)$ Use the rule above to obtain: $=-\dfrac{6}{10} + \dfrac{5}{10} \\=\dfrac{-6+5}{10} \\=\dfrac{-1}{10}$