Answer
$x^2+y^2-4y=0$
Work Step by Step
Center=$(0,2)$ Radius=$2$
Equation:
$(x-0)^2+(y-2)^2=2^2$
$\implies x^2+y^2-4y+4=4$
$\implies x^2+y^2-4y=0$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 9 - Conic Sections, Sequences, and Series - 9.1 Parabolas and Circles - 9.1 Exercises - Page 702: 61
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