#### Answer

$x^2+y^2-4y=0$

#### Work Step by Step

Center=$(0,2)$ Radius=$2$
Equation:
$(x-0)^2+(y-2)^2=2^2$
$\implies x^2+y^2-4y+4=4$
$\implies x^2+y^2-4y=0$

Published by
Brooks Cole

ISBN 10:
0-53449-636-9

ISBN 13:
978-0-53449-636-4

$x^2+y^2-4y=0$

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