Answer
$(x+2)^{2}+(y-3)^{2}=144$
Work Step by Step
The standard equation for a circle with centre $(h,k)$ and radius $r$ is given by
$(x-h)^{2}+(y-k)^{2}=r^{2}$
Given $(h,k)=(-2,3)$ and $r=12$.
identify $h$, $k$ and $r$:
$h=-2,$ $k=3$, $r=12$
determine the circle's equation:
$(x-(-2))^{2}+(y-3)^{2}=12^{2}$
The equation of the given circle is
$(x+2)^{2}+(y-3)^{2}=144$
