Answer
$1600$ feet
Work Step by Step
Given \begin{equation}
t=\sqrt{\frac{2 h}{32}}.
\end{equation} We are given that $t = 10$ seconds and want to find the height from which an object is dropped. Find $t = 10$ and solve for $h$. \begin{equation}
\begin{aligned}
10 & = \sqrt{\frac{2 h}{32}} \\
(10)^2&=\left( \sqrt{\frac{2 h}{32}} \right)^2\\
100& = \frac{2h}{32}\\
\frac{100\cdot 32}{2}& = h\\
1600&= h.
\end{aligned}
\end{equation} The object must be dropped from a height of $1600$ feet.
