Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.2 Simplifying, Adding, and Subtracting Radicals - 8.2 Exercises - Page 634: 77

Answer

$12 \sqrt{2}\; inches$.

Work Step by Step

Perimeter of the triangle is equal to the sum of all sides. The sides of the given triangle is $\sqrt{32}\; in,\sqrt{50}\; in$ and $\sqrt{18}\; in$ Add all sides. $=\sqrt{32}+\sqrt{50}+\sqrt{18}$ Factor radicands as a perfect square. $=\sqrt{16\cdot 2}+\sqrt{25\cdot 2}+\sqrt{9\cdot 2}$ Use product rule. $=\sqrt{16}\cdot \sqrt{2}+\sqrt{25}\cdot \sqrt{2}+\sqrt{9}\cdot \sqrt{2}$ Take square root of the perfect square. $=4\cdot \sqrt{2}+5\cdot \sqrt{2}+3\cdot \sqrt{2}$ Factor out $\sqrt{2}$. $=(4+5+3) \sqrt{2}$ Simplify. $=12 \sqrt{2}$. Hence, the perimeter is $12 \sqrt{2}\; inches$.
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