## Intermediate Algebra: Connecting Concepts through Application

$\color{blue}{17ab^2\sqrt{2ac}}$
Simplify each radical: $=7\sqrt{25a^2b^4(2ac)}-2ab\sqrt{81b^2(2ac)} \\=7\sqrt{5^2a^2(b^2)^2(2ac)}-2ab\sqrt{9^2b^2(2ac)} \\=7(5ab^2)\sqrt{2ac} - 2ab(9b)\sqrt{2ac} \\=35ab^2\sqrt{2ac}-18ab^2\sqrt{2ac}$ Combine like terms to obtain: $=(35-18)ab^2\sqrt{2ac} \\=\color{blue}{17ab^2\sqrt{2ac}}$