Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - Chapter Test - Page 608: 6

Answer

$\frac{2(m + 1)}{m + 4}$

Work Step by Step

Let's factor the denominators first: First denominator: $m^2 - m - 20 = (m - 5)(m + 4)$ Second denominator: $m^2 - 4m - 5 = (m - 5)(m + 1)$ Now, let's put the factored denominators back into the expression: $\frac{2m + 4}{(m - 5)(m + 4)} \div \frac{m + 2}{(m - 5)(m + 1)}$ To divide two expressions, we multiply the first one with the reciprocal of the second one: $\frac{2m + 4}{(m - 5)(m + 4)} • \frac{(m - 5)(m + 1)}{m + 2}$ Combine the two rational expressions into one by multiplying numerators together and denominators together: $\frac{(2m + 4)(m - 5)(m + 1)}{(m - 5)(m + 4)(m + 2)}$ Now, we want to cancel out the factors that are common in the numerators and denominators of each rational expression: $\frac{(2m + 4)(m + 1)}{(m + 4)(m + 2)}$ Factor out the common term in the numerator: $\frac{2(m + 2)(m + 1)}{(m + 4)(m + 2)}$ Finally, we can cancel out the common factor in both the numerator and denominator: $\frac{2(m + 1)}{m + 4}$
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