Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.1 Rational Functions and Variation - 7.1 Exercises - Page 564: 8

Answer

a) $C(r)=6.28 r$ b) $75.36$ inches c) $1.27$ inches

Work Step by Step

a) Let $C(r)$ be the circumference of the circle and $r$ be its radius. Since the circumference varies directly with the radius, we may write \begin{equation} \begin{aligned} C(r)&= kr, \end{aligned} \end{equation} where $k$ is the constant of proportionality that must be determined. Given that $C(5)= 31.4$ inches when $r=5$ inches, we can use this information to find $k$ as follows: \begin{equation} \begin{aligned} 31.4&= 5k\\ \frac{31.4}{5}&= k\\ 6.28&= k. \end{aligned} \end{equation} We can write \begin{equation} \begin{aligned} C(r)&= 6.28r. \end{aligned} \end{equation} b) Find $C(12)$ when $r= 12$. \begin{equation} \begin{aligned} C(r)&=6.28\cdot 12\\ &=75.36. \end{aligned} \end{equation} The circumference of a circle with a radius of $12$ inches is $75.36$ inches. c) Set $C(r) = 8$ and solve for $r$. \begin{equation} \begin{aligned} C(r)&=12\\ 6.28r &=8\\ r&= \frac{8}{6.28}\\ & \approx 1.27. \end{aligned} \end{equation} The radius of a circle with a circumference of $8$ inches is about $1.27$ inches.
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