Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 7 - Rational Functions - 7.1 Rational Functions and Variation - 7.1 Exercises - Page 564: 5

Answer

a) $C(n)=150n$ b) $\$1050$ c) 5 nights

Work Step by Step

a) Let $C(n)$ be the cost for a hotel room per night and $n$ be the number of nights. Because the cost of hotel varies directly with the number of night, we may write \begin{equation} \begin{aligned} C(n)&= kn, \end{aligned} \end{equation} vwhere $k$ is the constant of proportionality that must be determined. Given that $C(n)= 450$ when $n=3$, we can use this information to find $k$ as follows: \begin{equation} \begin{aligned}450&= 3k\\ \frac{450}{3}&= k\\ 150&= k\\C(n)&=150 n. \end{aligned} \end{equation} b) Find $C(7)$ when $n= 7$ \begin{equation} \begin{aligned} C(7)&=150\cdot 7\\ &=1050. \end{aligned} \end{equation} The cost of renting hotel for $7$ nights is $\$1050$. c) Set $C(n) = 800$ and solve for $n$. \begin{equation} \begin{aligned} C(n)&=150k\\ 150k &=800\\ k&= \frac{800}{150}\\ & \approx5.33. \end{aligned} \end{equation} You can stay for $5$ nights at the hotel with a budget of $\$800$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.