Answer
$h^{-1}(t) = 0.2^{t}$
Work Step by Step
$h(t) = \log_{0.2} t$
Let $h(t) = y$
$y = \log_{0.2} t$
Swap the variables $t$ and $y$ and then solve for $y$ to find the inverse:
$t = \log_{0.2} y$
$y = 0.2^{t}$
$h^{-1}(t) = 0.2^{t}$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - Chapter Review Exercises - Page 541: 7
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