#### Answer

$h^{-1} (x) = \log_5 x$

#### Work Step by Step

$h(x) = 5^{x}$
Let $h(x) = y$
$y = 5^{x}$
Swap the variables $x$ and $y$ and then solve for $y$ to find the inverse:
$x = 5^{y}$
$y = \log_5 x$
$h^{-1} (x) = \log_5 x$

Published by
Brooks Cole

ISBN 10:
0-53449-636-9

ISBN 13:
978-0-53449-636-4

$h^{-1} (x) = \log_5 x$

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