Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.6 Solving Logarithmic Equations - 6.6 Exercises: 9

Answer

$x \approx 4.1297$

Work Step by Step

$\ln (3x-5) = 2$ $\log_e (3x-5) = 2$ $e^{2} = 3x - 5$ $e^{2} + 5 = 3x$ $x = \frac{e^{2}+5}{3}$ $x \approx 4.1297$ Check: $\ln_e (3(\frac{e^{2}+5}{3})-5) \overset{?}{=} 2$ $\ln_e (e^{2}+5-5) \overset{?}{=} 2$ $\ln_e (e^{2}) \overset{?}{=} 2$ $2 = 2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.