Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.6 Solving Logarithmic Equations - 6.6 Exercises: 7

Answer

$x = 19.6$

Work Step by Step

$\log (5x + 2) = 2$ $\log_{10} (5x + 2) = 2$ $10^{2} = 5x + 2$ $100 = 5x + 2$ $100 -2 = 5x$ $98 = 5x$ $x = 19.6$ Check: $\log (5(19.6) + 2) \overset{?}{=}2$ $\log (98 + 2) \overset{?}{=}2$ $\log_{10} (100) \overset{?}{=}2$ $\log_{10} 10^{2} \overset{?}{=}2$ $2 = 2$
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