Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 528: 74

Answer

$x = -0.598$

Work Step by Step

$-7(0.8)^{x} + 10 = 2$ $-7(0.8)^{x} = 2 - 10$ $-7(0.8)^{x} = -8$ $(0.8)^{x} = \frac{8}{7}$ $x = \log_{0.8} (\frac{8}{7})$ $x = \frac{\log (\frac{8}{7})}{\log 0.8}$ $x = -0.59841...$ $x = -0.598$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.