Answer
$f^{-1}(x) = \ln_ (\frac{x}{4.2})$
Work Step by Step
$f(x) = 4.2e^{x}$
Let $f(x) = y$
$y = 4.2e^{x}$
Swap the variables $x$ and $y$ and then solve for $y$ to find the inverse:
$x = 4.2e^{y}$
$(e)^{y} = \frac{x}{4.2}$
$y = \ln (\frac{x}{4.2})$
$y = \ln_ (\frac{x}{4.2})$
$f^{-1}(x) = \ln_ (\frac{x}{4.2}).$