Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 526: 29

Answer

$n = 3$

Work Step by Step

$3(2)^{n+2} = 96$ $(2)^{n+2} = 32$ $(2)^{n+2} = (2)^{5}$ $n + 2 = 5$ $n = 5 -2$ $n = 3$
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