Answer
$x\approx2.227$
Work Step by Step
Take the log of both sides, and then use the power property.
$0.4^x=0.13$
$x\log0.4=\log0.13$
$x=\frac{\log0.13}{\log0.4}$
$x\approx2.227$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 6 - Logarithmic Functions - 6.5 Solving Exponential Equations - 6.5 Exercises - Page 526: 7
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