## Intermediate Algebra: Connecting Concepts through Application

a) $4849.05$ cm$^{3}$ b) $r = 8.89$ cm
a) $V = \frac{4}{3}\pi r^{3}$ $V = \frac{4}{3}\pi (10.5)^{3}$ $= \frac{4}{3}\pi (1157.625)$ $= \frac{4\pi (1157.625)}{3}$ by GDC / calculator $= \frac{4630.5\pi}{3}$ $= 4849.05$ cm$^{3}$ b) $2943 = \frac{4}{3}\pi r^{3}$ $2943 = \frac{4\pi r^{3}}{3}$ $8829 = 4\pi r^{3}$ $2207.25 = \pi r^{3}$ $\frac{2207.25}{\pi} = r^{3}$ $r = (\frac{2207.25}{\pi})^{\frac{1}{3}}$ $r = 8.89$ cm