Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 5 - Exponential Functions - 5.2 Solving Equations Using Exponent Rules - 5.2 Exercises: 77

Answer

$x = 2$

Work Step by Step

$3x^{5} + 94 = 190$ $3x^{5} = 190 - 94$ $3x^{5} = 96$ $x^{5} = 32$ $x = 32^{\frac{1}{5}}$ $x = 2$ Check: $3x^{5} + 94 \overset{?}{=} 190$ $3(2)^{5}+ 94 \overset{?}{=} 190$ $3(32) + 94 \overset{?}{=} 190$ $96 + 94 \overset{?}{=} 190$ $190 = 190$
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