Answer
$y=x^2+x-6$
Work Step by Step
The graph shows that the zeros of the function are $-3$ and $2$. This means that the function contains the factors $x+3$ and $x-2$.
Thus, the function is:
$y=(x+3)(x-2)\\
y=x^2-2x+3x-6\\
y=x^2+x-6$
(The graph does not show point toher than its zeros that have integral $y$-value so we have to assume that $a=1$).
