Answer
The solution set is $\left\{0, 2 \right\}$.
Work Step by Step
Factor out $x$:
$$x(x^2-4x+4)=0$$
Factor the trinomial to obtain:
$$x(x-2)(x-2)=0$$
Use the Zero-Product Property by equating each factor to zero, then solve each equation to obtain:
\begin{align*}
x&=0 &\text{or}& &x-2=0& &\text{or}& &x-2=0\\
x&=0 &\text{or}& &x=2& &\text{or}& &x=2\\
\end{align*}
Thus, the solution set is $\left\{0, 2 \right\}$.
