Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.3 Finding Quadratic Models - 4.3 Exercises - Page 334: 39

Answer

Model: $f(x) = 3.2x-15$ Domain: All real numbers Range: All real numbers

Work Step by Step

First make a scatter plot to determine the model type. Our scatter plot shows that the data is linear. Therefore find the slope of the line using any two points in the table. Take for example, $(-2, -21.4)\ ,\ (0,-15)$. $$\begin{aligned} m&= \frac{y_2-y_1}{x_2-x_1}\\ &= \frac{-15-(-21.4)}{0-(-2)}\\ &= \frac{6.4}{2}\\ &= 3.2 \end{aligned}$$ Find the equation of the line. Use the point $(6,4.2)$: $$\begin{aligned} y-y_1&= m(x-x_1)\\ y+4.2&= 3.2(x-6)\\ y&= 3.2x-19.2-4.2\\ y &= 3.2x-15 \end{aligned}$$ Hence the model is $$ f(x) = 3.2x-15.$$ The domain and range are: Domain: All real numbers Range: All real numbers
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.