Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.3 Finding Quadratic Models - 4.3 Exercises - Page 334: 38

Answer

Model: $ f(x) = 2.4(x+9)^2+3.5$ Domain: All real numbers Range: $[3.5,\infty )$

Work Step by Step

Step 1: Make a scatter plot of the data and choose a vertex point that may either be the lowest or highest point. The vertex of the data point can be seen to be at $(h,k)=(-9,3.5)$. Step 2: Set these into the standard vertex form of a parabola. This gives: $$\begin{aligned} f(x) &= a(x+9)^2+3.5. \end{aligned}$$ Step 3: Choose any point from the scatter plot to find the value of the constant, $a$. Let's take the point, $(x,y)=(-3,89.9)$ and insert these into the above equation to find $a$. $$\begin{aligned} 89.9 &= a(-3+9)^2+3.5\\ 89.9-3.5& = a(6)^2\\ 36a & = 86.4\\ a& = 2.4 \end{aligned}$$ Hence, the parabola that best fit the data is $$f(x) =2.4(x+9)^2+3.5.$$ The domain and range of this function are: Domain: All real numbers, Range: $[3.5,\infty )$.
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