Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 4 - Quadratic Functions - 4.3 Finding Quadratic Models - 4.3 Exercises - Page 331: 5

Answer

$f(x) =2(x+1.5)^2-20$

Work Step by Step

Start by graphing the data and the functions in the same figure window. $$\begin{aligned} f(x) &= 2(x+1)^2-20 \ ,\ h= -1\\ f(x) &= 2(x+1.2)^2-20 \ ,\ h= -1.2\\ f(x) &= 2(x+1.5)^2-20 \ ,\ h= -1.5\\ f(x) &= 2(x+1.8)^2-20 \ ,\ h= -1.8\\ \end{aligned}$$ The graph shows that the parabola that best fit the data is $$f(x) =2(x+1.5)^2-20.$$
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