Answer
$f(x) =4(x+2)^2-10$
Work Step by Step
Rewrite the given equation of the parabola so that it looks exactly like the general standard vertex form, $ f(x) = a(x-h)^2+k$
$$\begin{aligned}
f(x) &= 4x^2-10\\
&= 4(x+0)^2-10 \ ,\ h= 0\\
\end{aligned}$$ The best eyeball fit to the data can be found by setting the constant $h= 2$. Hence, we have $f(x) =4(x+2)^2-10 $ as the best eyeball fit to the data.