Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - Chapter Test - Page 289: 32



Work Step by Step

a$^3$-125b$^3$ This expression is a difference of cubes. If the cube root of the first term is a and the cube root of the second term is b, then the factorization is (a-b)(a$^2$+ab+b$^2$). So $\sqrt[3] {a^3}$=a $\sqrt[3] {125b^3}$=5b (a-5b)(a$^2$+5ab+25b$^2$).
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