Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 3 - Exponents, Polynomials and Functions - Chapter Test - Page 289: 28



Work Step by Step

7x$^3$-28x =7x(x$^2$-4) Inside the parenthesis is a difference of squares. If the square root of the first term is a and the square root of the second term is b, the factorization is (a+b)(a-b). $\sqrt {x^2}$=x and $\sqrt {4}$=2. So the factorization is 7x(x+2)(x-2).
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