#### Answer

$\text{Degree of Term 1: }
7
\\\text{Degree of Term 2: }
7
\\\text{Degree of Term 3: }
2
\\\text{Degree of Term 4: }
0
\\\text{Degree of the Polynomial: }
7$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
Use the definition of the degree of a term and the definition of the degree of a polynomial for the given polynomial, $
\dfrac{5}{7}r^2s^3t^2-\dfrac{3}{8}r^4st^2+\dfrac{4}{9}rs-\dfrac{5}{11}
.$
$\bf{\text{Solution Details:}}$
The degree of a term is the sum of the exponents of the variables in the term. Hence, the degree of each term in the given polynomial expression above is
\begin{array}{l}\require{cancel}
\text{Term 1: }
2+3+2=7
\\\text{Term 2: }
4+1+2=7
\\\text{Term 3: }
1+1=2
\\\text{Term 4: }
0
.\end{array}
The degree of a polynomial is the highest degree among all the terms.
Hence, the given polynomial has the following characteristics:
\begin{array}{l}\require{cancel}
\text{Degree of Term 1: }
7
\\\text{Degree of Term 2: }
7
\\\text{Degree of Term 3: }
2
\\\text{Degree of Term 4: }
0
\\\text{Degree of the Polynomial: }
7
.\end{array}