#### Answer

$\text{Degree of Term 1: }
4
\\\text{Degree of Term 2: }
4
\\\text{Degree of Term 3: }
0
\\\text{Degree of the Polynomial: }
4$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$
Use the definition of the degree of a term and the definition of the degree of a polynomial for the given polynomial, $
-14s^3t+6t^4-9
.$
$\bf{\text{Solution Details:}}$
The degree of a term is the sum of the exponents of the variables in a term. Hence, the degree of each term in the given polynomial expression above is
\begin{array}{l}\require{cancel}
\text{Term 1: }
3+1=4
\\\text{Term 2: }
4
\\\text{Term 3: }
0
.\end{array}
The degree of a polynomial is the highest degree among all the terms.
Hence, the given polynomial has the following characteristics:
\begin{array}{l}\require{cancel}
\text{Degree of Term 1: }
4
\\\text{Degree of Term 2: }
4
\\\text{Degree of Term 3: }
0
\\\text{Degree of the Polynomial: }
4
.\end{array}