## Intermediate Algebra: Connecting Concepts through Application

y=-$\frac{1}{3}$x+7
The slope of the desired line must be the opposite reciprocal of 3, therefore, it is -$\frac{1}{3}$. y-y$_1$=m(x-x$_1$) y-5=-$\frac{1}{3}$(x-6) y=-$\frac{1}{3}$x+2+5 y=-$\frac{1}{3}$x+7