## Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole

# Chapter 1 - Linear Functions - 1.5 Finding Equations of Lines - 1.5 Exercises - Page 77: 61

#### Answer

y=$\frac{2}{3}$x+12

#### Work Step by Step

10x-15y=-12 15y=10x+12 y=$\frac{2}{3}$x+$\frac{4}{5}$ m=$\frac{2}{3}$ y-y$_1$=m(x-x$_1$) y-8=$\frac{2}{3}$(x+6) y=$\frac{2}{3}$x+4+8 y=$\frac{2}{3}$x+12

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