## Intermediate Algebra: Connecting Concepts through Application

y=$-\frac{5}{4}x$ + $\frac{15}{2}$
Two points clearly on the line are (2,5) and (6,0). By moving across the line from one point to the next, we can clearly see that the slope goes down (negative) 5 and moves to the right 4 units, giving us a slope of m= $-\frac{5}{4}$. We can now use one of those points to find b: Plugging (6,0) into y=mx+b: 0=$-\frac{5}{4}(6)$ + b b=$\frac{15}{2}$ And our line is thus y=$-\frac{5}{4}x$ + $\frac{15}{2}$.