## Intermediate Algebra: Connecting Concepts through Application

$y = \frac{15}{2}x$ -$\frac{15}{2}$
Two points clearly on the line are (1,0) and (3,15). By going from one point to the other, we see that we move up 15 units and to the right 2 units, giving us a rise/run slope of m= $\frac{15}{2}$. We can use one of these points to plug into y=mx+b to find b: y=mx+b 0=$\frac{15}{2}$(1)+b 0=$\frac{15}{2}$+b $-\frac{15}{2}$ = b And so our line is $y = \frac{15}{2}x$ -$\frac{15}{2}$.