Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1 - Linear Functions - 1.1 Solving Linear Equations - 1.1 Exercises: 18

Answer

a. 24.5 psi b. approx. 485.71 seconds

Work Step by Step

We have the formula P = 35 - 0.07s, where P = pressure and s = seconds. For question "a": P = 35 - 0.07s P = 35 - 0.07 × 150 P = 35 - 10.5 P = 24.5 For question b: P = 35 - 0.07s 1 = 35 - 0.07s -34 = -0.07s s = 485.714286... So, to the nearest hundredth, s = 485.71.
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