## Intermediate Algebra: Connecting Concepts through Application

a. $N=-315.9t + 4809.8$ with $t=2$ $N=-315.9(2) + 4809.8$ $N=-631.8 + 4809.8$ $N=4178$ b. $t=2002 - 1990$ so $t=12$ $N=-315.9(12) + 4809.8$ $N=-3790.8 + 4809.8$ $N=1019$ c. $N=7337$ $7337=315.9(t) + 4809.8$ $7337-4809.8=315.9(t)$ $2527.2=315.9(t)$ $2527.2\div315.9=t$ $t=8$ $1990 + 8 = 1998$