Answer
$ \frac{(x-4)(x+2)}{x-3}$.
Work Step by Step
The given expression is
$\Rightarrow \frac{x^2-16}{x-3}\cdot \frac{x+2}{x+4}$
Factor $x^2-16$.
$=x^2-4^2$
Use special formula $A^2-B^2=(A-B)(A+B)$.
$=(x-4)(x+4)$
Substitute the factor into the given expression.
$\Rightarrow \frac{(x-4)(x+4)}{x-3}\cdot \frac{x+2}{x+4}$
Cancel common terms.
$\Rightarrow \frac{(x-4)(x+2)}{x-3}$.
