Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-9 - Cumulative Review - Page 763: 61

Answer

$22\sqrt{ 3a}-10\sqrt{a}$.

Work Step by Step

The given expression is $=7\sqrt{12a}+8\sqrt{3a}-10\sqrt{a}$ Factor radicands as square terms. $=7\sqrt{4\cdot 3a}+8\sqrt{3a}-10\sqrt{a}$ Simplify. $=7\cdot 2\sqrt{ 3a}+8\sqrt{3a}-10\sqrt{a}$ $=14\sqrt{ 3a}+8\sqrt{3a}-10\sqrt{a}$ Use the distributive property. $=(14+8)\sqrt{ 3a}-10\sqrt{a}$ Simplify. $=22\sqrt{ 3a}-10\sqrt{a}$.
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