Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-9 - Cumulative Review - Page 761: 7



Work Step by Step

$\ln(2x-5)=4$ $\implies 2x-5=e^4$ Add $5$ to both sides $2x=e^4+5$ Divide both sides by $2$ $x=\frac{e^4+5}{2}$ CHECK: $\ln(2\left(\frac{e^4+5}{2}\right)-5)=\ln(e^4+5-5)=\ln(e^4)=4$
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