Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 1-9 - Cumulative Review - Page 761: 6



Work Step by Step

$40\left(\frac{4}{5}\right)^n+300=320.48$ $40\left(\frac{4}{5}\right)^n=20.48$ Divde both sides by $40$ $\left(\frac{4}{5}\right)^n=\frac{64}{125}$ Take the logarithm of both sides base $\frac{4}{5}$ and we obtain $n=\log_{\frac{4}{5}}\frac{64}{125}=3$ CHECK: $40\left(\frac{4}{5}\right)^3+300=40\left(\frac{64}{125}\right)+300=20.48+300=320.48$
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