Answer
$x(3x-8)(7x-4)$
Work Step by Step
Given \begin{equation}
21 x^3-68 x^2+32 x.
\end{equation} Use factoring:
\begin{equation}
\begin{aligned}
21 x^3-68 x^2+32 x &= x\left(21 x^2-68 x+32\right)\\
&= x\left(21 x^2-56 x-12x+32\right)\\
& =x\left[(21 x^2-56 x)-(12x-32)\right]\\
& =x\left[(7x( 3x-8)-4(3x-8)\right]\\
& = x(3x-8)(7x-4).
\end{aligned}
\end{equation} The factored form of the given polynomial is:
\begin{equation}
21 x^3-68 x^2+32 x= x(3x-8)(7x-4).
\end{equation}
