Answer
$2(t+3)(4t-5)$
Work Step by Step
Given
\begin{equation} 8 t^2+14 t-30.
\end{equation} Factor the quadratic as shown below.
\begin{equation}
\begin{aligned}
8 t^2+14 t-30&= 2\left(4 t^2+7 t-15\right)\\
& =2\left(4 t^2+12 t-5t-15\right)\\
& =2\left[4t (t+3)-5(t+3)\right]\\
& = 2(t+3)(4t-5).
\end{aligned}
\end{equation} The factored form of the quadratic is:
\begin{equation}
8 t^2+14 t-30=2(t+3)(4t-5).
\end{equation}
