Answer
15
Work Step by Step
We start with
$9,500,000=9,939,000e^{-.003t}$
This gives:
$.9558=e^-.003t$
Using the natural log function, we get:
$-.003t=ln(.9558)$
$t=15$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 9 - Section 9.8 - Exponential and Logarithmic Equations and Problem Solving - Exercise Set - Page 592: 69
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